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Redox Reactions

23 NEET-UG practice questions on Redox Reactions, part of Chemistry. The first 23 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    Given below are two statements: Statement I: The oxidation number of oxygen in OF₂ is −2. Statement II: The oxidation number of hydrogen in NaH is +1. Choose the correct answer.

    1. ABoth Statement I and Statement II are correct
    2. BBoth Statement I and Statement II are incorrect
    3. CStatement I is correct but Statement II is incorrect
    4. DStatement I is incorrect but Statement II is correct
    Show answer

    Answer: B · Both Statement I and Statement II are incorrect

    Fluorine is always −1, so oxygen in OF₂ is +2. In metal hydrides, hydrogen is −1, as sodium is +1. Both statements are therefore false.

    • A: Both statements are false, as both use the usual values wrongly.
    • C: Statement I is false, since F forces oxygen to +2.
    • D: Statement II is false, since hydrogen is −1 with a metal.

    Remember this

    Oxygen is positive in fluorides, and hydrogen is −1 in metal hydrides.

  2. Question 2 · Hard

    Exactly 1.26 g of H₂C₂O₄·2H₂O is dissolved to make 250 mL of solution. A 25 mL portion is acidified and titrated with 0.02 M KMnO₄: 2MnO₄⁻ + 5C₂O₄²⁻ + 16H⁺ → 2Mn²⁺ + 10CO₂ + 8H₂O What volume of KMnO₄ is needed? (H₂C₂O₄·2H₂O = 126, H₂C₂O₄ = 90)

    1. A28 mL
    2. B125 mL
    3. C20 mL
    4. D50 mL
    Show answer

    Answer: C · 20 mL

    Oxalic acid = 1.26/126 = 0.01 mol in 250 mL, so 25 mL holds 1 mmol. KMnO₄ needed = 1 × 2/5 = 0.4 mmol, and the volume = 0.4/0.02 = 20 mL. Check by equivalents: 1 mmol × 2 = 2 meq, and V × 0.02 × 5 = 2 gives V = 20 mL.

    • A: This uses the anhydrous molar mass for hydrated crystals.
    • B: This inverts the ratio, using 5/2 instead of 2/5.
    • D: This takes a 1 : 1 mole ratio.

    Remember this

    In acid, 2 mol KMnO₄ react with 5 mol oxalate; use the hydrate's molar mass for the weighed crystals.

  3. Question 3 · Easy

    In the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), which species acts as the oxidising agent?

    1. ACu²⁺
    2. BZn
    3. CCu
    4. DZn²⁺
    Show answer

    Answer: A · Cu²⁺

    Cu²⁺ gains two electrons and is reduced to Cu, while it oxidises Zn to Zn²⁺. The species that is reduced is the oxidising agent.

    • B: Zn loses electrons, so it is the reducing agent.
    • C: Cu is a product, formed by reduction of Cu²⁺.
    • D: Zn²⁺ is a product, formed by oxidation of Zn.

    Remember this

    The oxidising agent is reduced; the reducing agent is oxidised.

  4. Question 4 · Medium

    An acidified permanganate solution oxidises iron(II): a MnO₄⁻ + b Fe²⁺ + c H⁺ → Mn²⁺ + Fe³⁺ + H₂O (not balanced) For the balanced ionic equation in lowest whole numbers, what are a, b and c?

    1. A1, 3, 8
    2. B1, 5, 4
    3. C1, 5, 8
    4. D2, 5, 16
    Show answer

    Answer: C · 1, 5, 8

    Mn goes from +7 to +2, gaining 5 electrons, and each Fe²⁺ loses 1, so b = 5 per MnO₄⁻. Four O need 8 H⁺ to form 4 H₂O. The charges match: −1 + 10 + 8 = +17 and +2 + 15 = +17.

    • A: This takes Mn as changing by three units, as it does in going to MnO₂.
    • B: This gives H⁺ only half of what the four oxygen atoms need.
    • D: This doubles MnO₄⁻ and H⁺ but not Fe²⁺.

    Remember this

    Balance electrons first, then O with H₂O, then H with H⁺, and confirm by charge.

  5. Question 5 · Easy

    What is the oxidation number of phosphorus in H₃PO₂?

    1. A−1
    2. B+5
    3. C+3
    4. D+1
    Show answer

    Answer: D · +1

    With H = +1 and O = −2, the sum is 3(+1) + x + 2(−2) = 0, so x = +1. Only the sum over all atoms matters, so count each atom in the formula.

    • A: This has the sign reversed.
    • B: This is the value in H₃PO₄.
    • C: This is the value in H₃PO₃.

    Remember this

    The oxidation numbers in a neutral molecule add up to zero.

  6. Question 6 · Medium

    Disproportionation occurs in which of the following reactions?

    1. ACaCO₃(s) → CaO(s) + CO₂(g)
    2. B2H₂O₂(aq) → 2H₂O(l) + O₂(g)
    3. C2Mg(s) + O₂(g) → 2MgO(s)
    4. D2KClO₃(s) → 2KCl(s) + 3O₂(g)

    Answer and explanation in LearnFree account

  7. Question 7 · Medium

    Arrange the following in increasing order of the oxidation number of nitrogen. A. NO₂ B. HNO₃ C. N₂O D. NH₃

    1. AD, A, C, B
    2. BD, C, A, B
    3. CB, A, C, D
    4. DC, D, A, B

    Answer and explanation in LearnFree account

  8. Question 9 · Hard

    In a neutral or weakly basic solution, permanganate oxidises sulphite to sulphate and is itself reduced to MnO₂. When the ionic equation a MnO₄⁻ + b SO₃²⁻ + c H₂O → d MnO₂ + e SO₄²⁻ + f OH⁻ is balanced with the smallest whole numbers, what are a, b and f?

    1. A2, 5, 2
    2. B3, 2, 2
    3. C2, 3, 2
    4. D2, 3, 4

    Answer and explanation in LearnFree account

  9. Question 10 · Medium

    Acidified potassium dichromate oxidises Fe²⁺ as follows: Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ → 2Cr³⁺ + 6Fe³⁺ + 7H₂O What volume of 0.10 M K₂Cr₂O₇ is needed to oxidise all the Fe²⁺ in 30 mL of 0.20 M FeSO₄ solution?

    1. A60 mL
    2. B20 mL
    3. C360 mL
    4. D10 mL

    Answer and explanation in LearnFree account

  10. Question 11 · Medium

    Match List-I with List-II. List-I (element in compound) A. Mn in KMnO₄ B. Cr in K₂Cr₂O₇ C. S in Na₂S₂O₃ D. Fe in Fe₃O₄ List-II (oxidation number, average where needed) I. +6 II. +8/3 III. +2 IV. +7 Choose the correct answer.

    1. AA-IV, B-III, C-I, D-II
    2. BA-IV, B-I, C-II, D-III
    3. CA-I, B-IV, C-III, D-II
    4. DA-IV, B-I, C-III, D-II

    Answer and explanation in LearnFree account

  11. Question 12 · Easy

    In the reaction 2S₂O₃²⁻ + I₂ → S₄O₆²⁻ + 2I⁻, the average oxidation number of sulphur changes from

    1. A+4 to +2.5
    2. B+2 to +2.5
    3. C+2.5 to +2
    4. D+2 to +5

    Answer and explanation in LearnFree account

  12. Question 13 · Hard

    Acidified KMnO₄ oxidises iron(II) oxalate, FeC₂O₄, completely: Fe²⁺ goes to Fe³⁺ and C₂O₄²⁻ goes to CO₂, while MnO₄⁻ is reduced to Mn²⁺. What volume of 0.020 M KMnO₄ is needed for 50 mL of 0.10 M FeC₂O₄?

    1. A150 mL
    2. B50 mL
    3. C375 mL
    4. D100 mL

    Answer and explanation in LearnFree account

  13. Question 14 · Medium

    Which of the following is NOT a redox reaction?

    1. A2Na + 2H₂O → 2NaOH + H₂
    2. BCl₂ + 2KI → 2KCl + I₂
    3. CCaCO₃ → CaO + CO₂
    4. D2KClO₃ → 2KCl + 3O₂

    Answer and explanation in LearnFree account

  14. Question 15 · Medium

    When white phosphorus is warmed with aqueous alkali, it reacts as follows: P₄ + 3OH⁻ + 3H₂O → PH₃ + 3H₂PO₂⁻ The oxidation number of phosphorus changes from 0 to

    1. A−3 and +3
    2. B−3 and +1
    3. C+3 and +1
    4. D−3 and +5

    Answer and explanation in LearnFree account

  15. Question 16 · Medium

    Arrange the metals below in increasing order of their tendency to lose electrons, using these observations: zinc displaces copper from CuSO₄ solution, copper displaces silver from AgNO₃ solution, and magnesium displaces zinc from ZnSO₄ solution. A. Ag B. Zn C. Cu D. Mg Choose the correct answer from the options given below.

    1. AD, B, C, A
    2. BC, A, B, D
    3. CA, C, B, D
    4. DA, B, C, D

    Answer and explanation in LearnFree account

  16. Question 17 · Medium

    Chlorine reacts with hot, concentrated NaOH: 3Cl₂ + 6OH⁻ → 5Cl⁻ + ClO₃⁻ + 3H₂O. What is the ratio of chlorine atoms reduced to chlorine atoms oxidised?

    1. A1 : 1
    2. B1 : 5
    3. C3 : 1
    4. D5 : 1

    Answer and explanation in LearnFree account

  17. Question 18 · Hard

    Consider the following statements. A. In NH₄NO₂ → N₂ + 2H₂O, nitrogen is both oxidised and reduced. B. Every decomposition reaction is a redox reaction. C. The reaction 2Cu⁺(aq) → Cu²⁺(aq) + Cu(s) is a disproportionation. D. The oxidation number of oxygen in KO₂ is −1/2. Choose the correct answer from the options given below.

    1. AA, B, C and D
    2. BA and C only
    3. CA, C and D only
    4. DC and D only

    Answer and explanation in LearnFree account

  18. Question 20 · Hard

    When the equation Cr₂O₇²⁻ + H₂S + H⁺ → Cr³⁺ + S + H₂O is balanced with the smallest whole-number coefficients, how many H⁺ ions are needed per Cr₂O₇²⁻ ion?

    1. A14
    2. B6
    3. C7
    4. D8

    Answer and explanation in LearnFree account

  19. Question 22 · Medium

    In acidic solution, 2MnO₄⁻ + 5H₂O₂ + 6H⁺ → 2Mn²⁺ + 5O₂ + 8H₂O. What volume of 0.020 M KMnO₄ is needed to react completely with 25 mL of 0.050 M H₂O₂?

    1. A62.5 mL
    2. B156 mL
    3. C10 mL
    4. D25 mL

    Answer and explanation in LearnFree account

  20. Question 23 · Medium

    Given below are two statements: Statement I: In a disproportionation reaction, an element in one oxidation state is simultaneously oxidised and reduced. Statement II: Fluorine undergoes disproportionation when it reacts with alkali. Choose the correct answer.

    1. AStatement I is incorrect but Statement II is correct
    2. BStatement I is correct but Statement II is incorrect
    3. CBoth Statement I and Statement II are incorrect
    4. DBoth Statement I and Statement II are correct

    Answer and explanation in LearnFree account

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