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Dual Nature of Radiation & Matter

31 NEET-UG practice questions on Dual Nature of Radiation & Matter, part of Physics. The first 25 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    A deuteron and an α-particle, both initially at rest, are accelerated through the same potential difference. What is the ratio of the de Broglie wavelength of the deuteron to that of the α-particle?

    1. A4
    2. B2
    3. C1/2
    4. D√2
    Show answer

    Answer: B · 2

    λ = h/√(2mqV), so at the same V, λ is proportional to 1/√(mq). Deuteron: mq = 2 × 1 = 2. α-particle: mq = 4 × 2 = 8. The ratio is √(8/2) = 2.

    • A: The square root was not taken.
    • C: The ratio has been inverted.
    • D: The factor from the charge was left out, using 1/√m only.

    Remember this

    Through the same potential, de Broglie wavelength varies as 1/√(mq), so a larger mass and charge both shorten it.

  2. Question 2 · Hard

    A metal is lit in turn by light of wavelength 200 nm and of 400 nm. The stopping potential with 200 nm is three times that with 400 nm. Taking hc = 1240 eV nm, find the work function of the metal.

    1. A4.65 eV
    2. B3.1 eV
    3. C7.75 eV
    4. D1.55 eV
    Show answer

    Answer: D · 1.55 eV

    Photon energies are 1240/200 = 6.2 eV and 1240/400 = 3.1 eV. Then 6.2 - φ = 3(3.1 - φ), so 2φ = 3.1 and φ = 1.55 eV. Check: stopping potentials 4.65 V and 1.55 V, ratio 3.

    • A: This is the stopping energy with 200 nm light.
    • B: This is the photon energy of 400 nm light, not the work function.
    • C: The factor of 3 was applied to the wrong wavelength.

    Remember this

    Write eV₀ = hc/λ - φ for each wavelength and solve the pair; the work function does not change.

  3. Question 3 · Medium

    In a photoelectric experiment, the frequency of light is kept fixed above threshold while its intensity is doubled. What happens to the saturation current and the stopping potential?

    1. ABoth saturation current and stopping potential double
    2. BSaturation current doubles; stopping potential is unchanged
    3. CBoth saturation current and stopping potential are unchanged
    4. DSaturation current is unchanged; stopping potential doubles
    Show answer

    Answer: B · Saturation current doubles; stopping potential is unchanged

    Doubling intensity doubles the photons per second, and so the electrons emitted per second and the saturation current. The stopping potential depends on hν - φ, which has not changed.

    • A: Stopping potential does not depend on intensity.
    • C: More photons per second do raise the saturation current.
    • D: This reverses the roles of intensity and frequency.

    Remember this

    Intensity controls photocurrent; frequency and work function control stopping potential.

  4. Question 4 · Easy

    Light below a metal's threshold frequency falls on it, and its intensity is increased many times. What happens to photoelectric emission?

    1. AEmission begins after a long delay
    2. BNo emission occurs at any intensity
    3. CEmission occurs with zero kinetic energy
    4. DEmission begins once the intensity is high enough
    Show answer

    Answer: B · No emission occurs at any intensity

    Each photon has energy hν, and one electron absorbs one photon. Below threshold, hν is less than the work function, so no electron can escape, however many photons arrive.

    • A: Emission is instantaneous when it occurs, and here it does not occur at all.
    • C: An electron cannot escape without energy at least equal to the work function.
    • D: More photons do not help, as one photon gives its energy to one electron.

    Remember this

    Emission depends on frequency, not intensity; above threshold, intensity sets the number of electrons, frequency their energy.

  5. Question 5 · Easy

    Photons of energy 5.0 eV strike a metal of work function 2.0 eV. What stopping potential do the emitted electrons have?

    1. A7.0 V
    2. B5.0 V
    3. C3.0 V
    4. D2.5 V
    Show answer

    Answer: C · 3.0 V

    Einstein's equation gives K_max = hν - φ = 5.0 - 2.0 = 3.0 eV. The stopping potential satisfies eV₀ = K_max, so V₀ = 3.0 V.

    • A: The work function was added instead of subtracted.
    • B: The work function was ignored.
    • D: The photon energy was divided by the work function.

    Remember this

    eV₀ = hν - φ, so the stopping potential in volts equals the maximum kinetic energy in eV.

  6. Question 6 · Medium

    Assertion A: Graphs of stopping potential against frequency for two different metals are parallel straight lines. Reason R: The slope of each graph equals the work function of the metal divided by e. Choose the correct answer.

    1. ABoth A and R are correct but R is not the correct explanation of A
    2. BA is not correct but R is correct
    3. CBoth A and R are correct and R is the correct explanation of A
    4. DA is correct but R is not correct

    Answer and explanation in LearnFree account

  7. Question 7 · Medium

    Stopping potential is plotted against frequency for two metals P and Q. If light of frequency 10 × 10¹⁴ Hz falls on each, what is the ratio of the maximum kinetic energy of photoelectrons from P to that from Q?

    Figure: MedExams
    Two parallel straight lines, P and Q, of stopping potential against frequency, starting from different points on the frequency axis.
    1. A3 : 2
    2. B1 : 1
    3. C5 : 3
    4. D2 : 3

    Answer and explanation in LearnFree account

  8. Question 8 · Easy

    Maximum kinetic energy of photoelectrons from a metal is plotted against the frequency of the incident light. Using h = 6.6 × 10⁻³⁴ J s, what is the work function of the metal?

    Figure: MedExams
    A straight line of maximum kinetic energy against frequency with three plotted points.
    1. A9.9 × 10⁻¹⁹ J
    2. B5.0 × 10⁻¹⁹ J
    3. C3.3 × 10⁻¹⁹ J
    4. D6.6 × 10⁻¹⁹ J

    Answer and explanation in LearnFree account

  9. Question 9 · Medium

    A photocell is lit by light of one frequency at two intensities, I₁ > I₂. Which graph correctly shows photocurrent i against anode potential V for both?

    Figure: MedExams
    Four graphs of photocurrent against anode potential, labelled A to D, each with two curves marked I1 and I2.
    1. AGraph A
    2. BGraph C
    3. CGraph D
    4. DGraph B

    Answer and explanation in LearnFree account

  10. Question 10 · Hard

    A proton (mass m, charge e), a deuteron (mass 2m, charge e) and an alpha particle (mass 4m, charge 2e) are each accelerated from rest through a potential difference V. Lines P, Q and R plot their de Broglie wavelengths against 1/√V. Identify the lines.

    Figure: MedExams
    Three straight lines from the origin, labelled P, Q and R, of de Broglie wavelength against 1/√V.
    1. AP: proton, Q: alpha particle, R: deuteron
    2. BP: alpha particle, Q: deuteron, R: proton
    3. CP: deuteron, Q: proton, R: alpha particle
    4. DP: proton, Q: deuteron, R: alpha particle

    Answer and explanation in LearnFree account

  11. Question 11 · Hard

    Light of wavelength λ falling on a metal gives a stopping potential of 2V₀. Light of wavelength 1.5λ on the same metal gives a stopping potential of V₀. What is the threshold wavelength of the metal?

    1. A4.5λ
    2. B2λ
    3. C3λ
    4. D6λ

    Answer and explanation in LearnFree account

  12. Question 12 · Medium

    An electron starts from rest and is accelerated through a potential difference of 100 V. What is its de Broglie wavelength, approximately?

    1. A12.3 nm
    2. B0.0123 nm
    3. C0.123 nm
    4. D1.23 nm

    Answer and explanation in LearnFree account

  13. Question 13 · Medium

    A metal surface has a work function of 2.48 eV. What is the longest wavelength of light that can eject photoelectrons from it? Take hc = 1240 eV nm.

    1. A500 nm
    2. B1000 nm
    3. C250 nm
    4. D3075 nm

    Answer and explanation in LearnFree account

  14. Question 14 · Easy

    In the photoelectric effect, emission starts with no noticeable delay even when the incident light is very weak. What does this support?

    1. AElectrons slowly collect energy from the light wave
    2. BLight energy is delivered in discrete packets, each absorbed by a single electron
    3. CThe work function of a metal falls when light is weak
    4. DLight energy spreads evenly over the whole surface

    Answer and explanation in LearnFree account

  15. Question 15 · Medium

    Given below are two statements: Statement I: The maximum kinetic energy of photoelectrons increases linearly with the frequency of the incident light, above the threshold. Statement II: The slope of the graph of stopping potential against frequency is the same for all metals. Choose the correct answer.

    1. ABoth Statement I and Statement II are incorrect
    2. BBoth Statement I and Statement II are correct
    3. CStatement I is correct but Statement II is incorrect
    4. DStatement I is incorrect but Statement II is correct

    Answer and explanation in LearnFree account

  16. Question 16 · Medium

    For each of two different metals, the stopping potential V₀ is measured at several frequencies ν and plotted against ν. How do the two straight lines compare?

    1. AThey pass through the origin with slopes set by the work functions
    2. BThey are parallel, with slope e/h, and coincide
    3. CThey meet at one point on the frequency axis but have different slopes
    4. DThey are parallel, with slope h/e, but cut the frequency axis at different points

    Answer and explanation in LearnFree account

  17. Question 17 · Hard

    A 6.6 mW beam of light of wavelength 600 nm falls on a metal of work function 1.8 eV. On average one photoelectron is emitted for every 100 incident photons, and all of them reach the collector. Taking h = 6.6 × 10⁻³⁴ J s, c = 3 × 10⁸ m/s and e = 1.6 × 10⁻¹⁹ C, what saturation current flows?

    1. A32 µA
    2. B3.2 mA
    3. C0.32 µA
    4. D32 mA

    Answer and explanation in LearnFree account

  18. Question 18 · Medium

    Suppose a proton and an alpha particle are moving with equal kinetic energies. Taking the mass of the alpha particle as four times that of the proton, what is the ratio of the de Broglie wavelength of the proton to that of the alpha particle?

    1. A1 : 2
    2. B4 : 1
    3. C2 : 1
    4. D2√2 : 1

    Answer and explanation in LearnFree account

  19. Question 19 · Easy

    Light falls on a metal surface and ejects photoelectrons. Which change increases the maximum kinetic energy of the emitted electrons?

    1. ARaising the intensity of the light
    2. BRaising the frequency of the light
    3. CKeeping the light on for a longer time
    4. DMaking the collector more positive

    Answer and explanation in LearnFree account

  20. Question 20 · Medium

    Ultraviolet light of wavelength 310 nm falls on a metal of work function 2.5 eV. Taking hc = 1240 eV nm, what stopping potential is needed to cut off the photocurrent?

    1. A4 V
    2. B2.5 V
    3. C1.5 V
    4. D6.5 V

    Answer and explanation in LearnFree account

  21. Question 21 · Medium

    A ball of mass 0.1 kg moving at 6.6 m/s has a de Broglie wavelength of 10⁻³³ m. Why are its wave properties never observed in practice?

    1. AIts speed is too low for a matter wave to form
    2. BIts wavelength is far smaller than any aperture or obstacle, so no diffraction can be detected
    3. CThe ball is uncharged, and only charged particles have matter waves
    4. DBodies of macroscopic mass have no de Broglie wave at all

    Answer and explanation in LearnFree account

  22. Question 22 · Easy

    Taking h = 6.6 × 10⁻³⁴ J s and c = 3 × 10⁸ m/s, what is the momentum of a photon of wavelength 660 nm?

    1. A3.3 × 10⁻³⁶ kg m/s
    2. B1.0 × 10⁻²⁷ kg m/s
    3. C3.0 × 10⁻¹⁹ kg m/s
    4. D1.0 × 10⁻²⁴ kg m/s

    Answer and explanation in LearnFree account

  23. Question 23 · Medium

    An electron and a photon have the same de Broglie wavelength. Which quantity must then be the same for both?

    1. AEnergy
    2. BMass
    3. CMomentum
    4. DSpeed

    Answer and explanation in LearnFree account

  24. Question 24 · Hard

    Photons emitted when hydrogen atoms fall from n = 2 to n = 1 strike a metal of work function 4.2 eV. Taking Eₙ = −13.6/n² eV, and the de Broglie wavelength of an electron of kinetic energy K (in eV) as 1.227/√K nm, what is the de Broglie wavelength of the fastest photoelectrons?

    1. A0.32 nm
    2. B0.20 nm
    3. C0.38 nm
    4. D0.50 nm

    Answer and explanation in LearnFree account

  25. Question 25 · Easy

    Taking hc = 1240 eV nm, what is the energy of a photon of wavelength 620 nm?

    1. A3.2 × 10⁻¹⁹ eV
    2. B2.0 eV
    3. C20 eV
    4. D0.5 eV

    Answer and explanation in LearnFree account

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