Skip to content
GetMyScrub

Electrostatic Potential & Capacitance

39 NEET-UG practice questions on Electrostatic Potential & Capacitance, part of Physics. The first 25 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    How much work is needed to assemble three charges, each of +1 µC, at the corners of an equilateral triangle of side 0.3 m, starting from far apart? Take 1/(4πε₀) = 9 × 10⁹ N m²/C².

    1. A0.03 J
    2. B0.18 J
    3. C0.09 J
    4. D0.06 J
    Show answer

    Answer: C · 0.09 J

    Each pair contributes kq²/a = 9 × 10⁹ × 10⁻¹²/0.3 = 0.03 J. Three charges form 3 pairs, so the total = 0.09 J. Check: bringing the second charge costs 0.03 J and the third 0.06 J.

    • A: This counts only one pair.
    • B: This counts each pair twice.
    • D: This counts only two pairs.

    Remember this

    The potential energy of a system is the sum over all pairs, each pair counted once.

  2. Question 2 · Medium

    A parallel plate capacitor is charged and then disconnected from the battery. A dielectric slab of constant K is then inserted to fill the whole gap. A. The capacitance becomes K times its value. B. The charge on the plates stays unchanged. C. The energy stored decreases. D. The potential difference between the plates increases. Which statements are correct?

    1. AA, B and C only
    2. BA, B and D only
    3. CC and D only
    4. DA and B only
    Show answer

    Answer: A · A, B and C only

    Capacitance becomes KC. The isolated plates keep their charge Q. So V = Q/(KC) falls by K, and energy Q²/(2KC) falls by K, which makes C true and D false.

    • B: D is false: V falls when C rises at fixed Q.
    • C: This misses A and B and includes the false D.
    • D: This misses C, since the energy Q²/2C falls.

    Remember this

    Battery removed: Q stays, V and U fall by K. Battery connected: V stays, Q and U rise by K.

  3. Question 3 · Easy

    Arrange these combinations of three identical capacitors, each of capacitance C, in increasing order of equivalent capacitance. A. All three in series B. Two in series, with the third in parallel to this pair C. Two in parallel, with the third in series with this pair D. All three in parallel

    1. AA, C, D, B
    2. BC, A, B, D
    3. CA, C, B, D
    4. DA, B, C, D
    Show answer

    Answer: C · A, C, B, D

    A gives C/3. C gives (2C × C)/(3C) = 2C/3. B gives C/2 + C = 3C/2. D gives 3C. The increasing order is A, C, B, D.

    • A: This ranks 3C below 3C/2.
    • B: This ranks 2C/3 below C/3.
    • D: This interchanges the two mixed combinations, 3C/2 and 2C/3.

    Remember this

    Series lowers capacitance below the smallest member; parallel simply adds the values.

  4. Question 4 · Medium

    A 4 µF capacitor charged to 100 V is connected in parallel to an uncharged 6 µF capacitor. How much energy is lost in the process?

    1. A24 mJ
    2. B12 mJ
    3. C8 mJ
    4. D20 mJ
    Show answer

    Answer: B · 12 mJ

    Before: (1/2)(4 × 10⁻⁶)(100)² = 20 mJ. Common V = 400 µC/10 µF = 40 V, so after: (1/2)(10 × 10⁻⁶)(40)² = 8 mJ. Loss = 12 mJ. Check: (1/2)[C₁C₂/(C₁ + C₂)]V² = (1/2)(2.4 × 10⁻⁶)(100)² = 12 mJ.

    • A: This leaves out the factor 1/2 in the loss formula.
    • C: This is the energy left after sharing, not the loss.
    • D: This is the energy before sharing.

    Remember this

    Charge is conserved on sharing, but energy is always lost, as (1/2)[C₁C₂/(C₁ + C₂)](V₁ − V₂)².

  5. Question 5 · Hard

    Capacitors of 2 µF and 3 µF are connected in series across a 100 V supply. After charging, they are removed and reconnected to each other with like-charged plates joined. What is the final common potential difference?

    1. A48 V
    2. BZero
    3. C50 V
    4. D100 V
    Show answer

    Answer: A · 48 V

    In series, Ceq = 1.2 µF, so each capacitor holds Q = 120 µC (60 V and 40 V). With like plates joined, the total charge is 240 µC on 5 µF, so V = 48 V. Check: (2 × 60 + 3 × 40)/5 = 240/5 = 48 V.

    • B: This is the result of joining unlike plates, where the equal charges cancel.
    • C: This takes the plain mean of 60 V and 40 V.
    • D: This assumes the capacitors keep the supply voltage.

    Remember this

    Series capacitors carry equal charge; like plates joined add charges, while unlike plates joined subtract them.

  6. Question 6 · Easy

    How is the electric field oriented at any point on an equipotential surface?

    1. AAt 45° to the surface
    2. BParallel to the nearest charge
    3. CTangent to the surface
    4. DNormal to the surface

    Answer and explanation in LearnFree account

  7. Question 7 · Medium

    A conducting sphere of radius 10 cm carries a charge of 2 nC. Taking 1/(4πε₀) = 9 × 10⁹ N m²/C², what are the electric field and the potential at a point 5 cm from its centre?

    1. A0 and 360 V
    2. B7200 N/C and 360 V
    3. C0 and 180 V
    4. D1800 N/C and 180 V

    Answer and explanation in LearnFree account

  8. Question 8 · Hard

    A 6 µF air-filled parallel plate capacitor is charged to 30 V and disconnected from the battery. A slab of dielectric constant 3, of thickness half the plate separation, is then placed between the plates. What is the new potential difference between the plates?

    1. A20 V
    2. B30 V
    3. C15 V
    4. D10 V

    Answer and explanation in LearnFree account

  9. Question 9 · Medium

    A cell is connected to the capacitor network drawn here. Find the charge on the 3 µF capacitor in the steady state.

    Figure: MedExams
    A 12 V cell across two parallel branches: one with 3 µF and 6 µF capacitors in series, the other with a 4 µF capacitor.
    1. A72 µC
    2. B48 µC
    3. C36 µC
    4. D24 µC

    Answer and explanation in LearnFree account

  10. Question 10 · Easy

    Equally spaced parallel equipotential surfaces of a uniform electric field are drawn in the figure. What are the magnitude and direction of the field?

    Figure: MedExams
    Four vertical dashed equipotential lines with their potentials marked, each 5 cm from the next.
    1. A200 V/m, from the 10 V surface towards the 40 V surface
    2. B2 V/m, from the 40 V surface towards the 10 V surface
    3. C200 V/m, from the 40 V surface towards the 10 V surface
    4. D600 V/m, from the 40 V surface towards the 10 V surface

    Answer and explanation in LearnFree account

  11. Question 11 · Medium

    Which plot gives the potential V at distance r from the centre of a thin metal shell of radius R holding charge +Q, far from all other bodies?

    Figure: MedExams
    Four graphs of V against r, labelled A to D, with the radius R marked on the r axis.
    1. AGraph C
    2. BGraph A
    3. CGraph D
    4. DGraph B

    Answer and explanation in LearnFree account

  12. Question 12 · Hard

    Two capacitors were charged separately to the voltages marked and then disconnected from their cells. Note the polarity of each. How much energy is lost as heat after switch S is closed and charges settle?

    Figure: MedExams
    A 2 µF capacitor at 30 V and a 4 µF capacitor at 6 V joined by two wires, with an open switch in the top wire and plate polarities marked.
    1. A864 µJ
    2. B108 µJ
    3. C972 µJ
    4. D384 µJ

    Answer and explanation in LearnFree account

  13. Question 13 · Medium

    Without any slab, a parallel plate capacitor has a capacitance of 10 µF. A slab fills the gap as drawn, covering the whole plate area. What is the new capacitance?

    Figure: MedExams
    Two horizontal plates separated by d; the upper half of the gap is air and the lower half is a slab of dielectric constant 4.
    1. A16 µF
    2. B25 µF
    3. C8 µF
    4. D40 µF

    Answer and explanation in LearnFree account

  14. Question 14 · Hard

    A 2 µF capacitor charged to 100 V and a 3 µF capacitor charged to 50 V are disconnected from their sources. The positive plate of each is then joined to the negative plate of the other. Find the final common potential difference and the energy lost as heat.

    1. A10 V and 0.25 mJ
    2. B70 V and 1.5 mJ
    3. C10 V and 13.5 mJ
    4. D70 V and 12.25 mJ

    Answer and explanation in LearnFree account

  15. Question 15 · Medium

    Given below are two statements: Statement I: For a charged conductor in electrostatic equilibrium, every point of its volume and its surface is at the same potential. Statement II: The electric potential everywhere inside a charged hollow conducting sphere is zero. Choose the correct answer.

    1. ABoth Statement I and Statement II are correct
    2. BStatement I is incorrect but Statement II is correct
    3. CBoth Statement I and Statement II are incorrect
    4. DStatement I is correct but Statement II is incorrect

    Answer and explanation in LearnFree account

  16. Question 16 · Medium

    An uncharged hollow metal box, with nothing inside its cavity, is placed in a strong uniform external electric field. What is the electric field inside the empty cavity?

    1. AZero at every point of the cavity
    2. BNon-zero but weaker than the external field
    3. CEqual to the external field
    4. DZero only at the centre of the cavity

    Answer and explanation in LearnFree account

  17. Question 17 · Easy

    A parallel plate capacitor stays connected to a battery while a slab of dielectric constant K is slid in to fill the whole space between its plates. How do the charge on the plates and the energy stored change?

    1. ABoth become K times their earlier values
    2. BCharge stays the same; energy becomes 1/K times
    3. CBoth stay the same
    4. DCharge becomes K times; energy stays the same

    Answer and explanation in LearnFree account

  18. Question 18 · Medium

    Point charges of +4 µC and -2 µC are held 6 m apart. At which point on the line segment joining them is the electric potential zero?

    1. A2 m from the +4 µC charge
    2. BNo such point exists between them
    3. C4 m from the +4 µC charge
    4. D3 m from each charge

    Answer and explanation in LearnFree account

  19. Question 19 · Medium

    A parallel plate capacitor has a capacitance of 6 µF with air between its plates. A slab of dielectric constant 2, of the same area as the plates and half as thick as the gap, is placed between them. What is the new capacitance?

    1. A9 µF
    2. B4.5 µF
    3. C8 µF
    4. D12 µF

    Answer and explanation in LearnFree account

  20. Question 20 · Easy

    A point charge of +2 µC moves from point P, at a potential of 50 V, to point Q, at a potential of 20 V. How much work does the electric field do on the charge?

    1. A+60 µJ
    2. B+15 µJ
    3. C-60 µJ
    4. D+140 µJ

    Answer and explanation in LearnFree account

  21. Question 21 · Medium

    Capacitors of 2 µF, 3 µF and 6 µF are joined in series across a 12 V battery. In the steady state, what potential difference appears across the 2 µF capacitor?

    1. A6 V
    2. B4 V
    3. C2 V
    4. D12 V

    Answer and explanation in LearnFree account

  22. Question 22 · Easy

    Some molecules carry a permanent electric dipole moment even when no external field acts on them. Which of these is such a polar molecule?

    1. AH₂
    2. BH₂O
    3. CCH₄
    4. DO₂

    Answer and explanation in LearnFree account

  23. Question 23 · Hard

    Two air-filled capacitors, C₁ and C₂, each of 4 µF, are connected in series across a 12 V battery, which stays connected. A dielectric slab of dielectric constant 3 is then inserted to fill C₁ completely. What is the potential difference across C₂ after the charges settle?

    1. A4 V
    2. B3 V
    3. C9 V
    4. D6 V

    Answer and explanation in LearnFree account

  24. Question 24 · Medium

    Given below are two statements: Statement I: The capacitance of a parallel plate capacitor depends on the amount of charge placed on its plates. Statement II: When a dielectric slab is slid between the plates of a charged capacitor that has been disconnected from its battery, the energy stored in the capacitor decreases. Choose the correct answer.

    1. ABoth Statement I and Statement II are correct
    2. BStatement I is correct but Statement II is incorrect
    3. CStatement I is incorrect but Statement II is correct
    4. DBoth Statement I and Statement II are incorrect

    Answer and explanation in LearnFree account

  25. Question 25 · Easy

    How much energy is stored in a 4 µF capacitor charged to a potential difference of 50 V?

    1. A10 mJ
    2. B0.2 mJ
    3. C0.1 mJ
    4. D5 mJ

    Answer and explanation in LearnFree account

14 more Electrostatic Potential & Capacitance questions

Answer them one by one, keep your score and see your weak topics in Learn. Signed-out visitors try 25 per exam; sign in with Google to see them all.

Study Physics