Skip to content
GetMyScrub

Mechanical Properties of Solids

18 NEET-UG practice questions on Mechanical Properties of Solids, part of Physics. The first 18 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    Arrange these points on the stress-strain curve of a ductile metal in the order in which they are reached as the strain increases. A. Fracture point B. Yield point C. Proportional limit D. Point of ultimate tensile strength

    1. AB, D, C, A
    2. BB, C, D, A
    3. CC, B, D, A
    4. DC, D, B, A
    Show answer

    Answer: C · C, B, D, A

    Stress is proportional to strain up to the proportional limit. The yield point comes next, where plastic behaviour begins. Stress then rises to its greatest value, the ultimate tensile strength, and the wire finally breaks at the fracture point.

    • A: This puts the proportional limit after the plastic region.
    • B: The proportional limit comes before the yield point.
    • D: Ultimate strength lies beyond the yield point, not before it.

    Remember this

    The maximum stress occurs before fracture; between these two points the stress falls as the wire thins.

  2. Question 2 · Easy

    In an experiment to find Young's modulus, a wire 2 m long with a cross-section of 1 mm² stretches by 1 mm under a load of 100 N. What value of Young's modulus do these readings give?

    1. A2 × 10⁸ Pa
    2. B5 × 10¹⁰ Pa
    3. C2 × 10⁵ Pa
    4. D2 × 10¹¹ Pa
    Show answer

    Answer: D · 2 × 10¹¹ Pa

    Y = FL/(A ΔL) = (100 × 2)/(10⁻⁶ × 10⁻³) = 2 × 10¹¹ Pa.

    • A: This does not convert the extension from millimetres to metres.
    • B: This divides by the length instead of multiplying by it.
    • C: This does not convert the area from mm² to m².

    Remember this

    Convert to SI first: 1 mm² = 10⁻⁶ m² and 1 mm = 10⁻³ m.

  3. Question 3 · Medium

    A sealed 2 litre sample of a liquid of bulk modulus 2 × 10⁹ Pa experiences a pressure rise of 4 × 10⁶ Pa. By how much does its volume decrease?

    1. A2 cm³
    2. B1 cm³
    3. C0.4 cm³
    4. D4 cm³
    Show answer

    Answer: D · 4 cm³

    B = Δp/(ΔV/V), so ΔV/V = 4 × 10⁶/(2 × 10⁹) = 2 × 10⁻³. Then ΔV = 2000 cm³ × 2 × 10⁻³ = 4 cm³.

    • A: This takes the original volume as 1 litre.
    • B: This divides the strain by the 2 litres instead of multiplying.
    • C: This makes a power-of-ten slip in the conversion from litres to cm³.

    Remember this

    Volumetric strain = Δp/B; multiply it by the original volume to get the volume change.

  4. Question 4 · Medium

    Load against extension is plotted for a wire 2 m long with a cross-section of 1 mm². What is the Young's modulus of its material?

    Figure: MedExams
    Straight load-extension line through the origin, with scales in newtons and millimetres.
    1. A2 × 10¹¹ Pa
    2. B2 × 10⁵ Pa
    3. C1 × 10¹¹ Pa
    4. D2 × 10⁸ Pa
    Show answer

    Answer: A · 2 × 10¹¹ Pa

    From the graph, 40 N gives 0.4 mm. Stress = 40/10⁻⁶ = 4 × 10⁷ Pa and strain = (0.4 × 10⁻³)/2 = 2 × 10⁻⁴, so Y = 2 × 10¹¹ Pa. Direct use of Y = FL/(AΔL) gives 80/(4 × 10⁻¹⁰), the same value.

    • B: Leaves the area in mm², not converting it to m².
    • C: Leaves out the wire's length of 2 m.
    • D: Treats the extension in mm without converting it to metres.

    Remember this

    Y = FL/(AΔL) = (slope of load-extension) × L/A, in SI units.

  5. Question 5 · Easy

    Match List-I with List-II for the stress-strain curve of a metal wire shown. List-I (Point on the curve) A. P B. Q C. R D. S List-II (What it marks) I. Fracture point II. Proportional limit III. Ultimate tensile strength IV. Yield point

    Figure: MedExams
    Stress-strain curve: a straight part, a bend, a rise to a peak and a fall, with four labelled points.
    1. AA-IV, B-II, C-III, D-I
    2. BA-II, B-IV, C-III, D-I
    3. CA-II, B-III, C-IV, D-I
    4. DA-II, B-IV, C-I, D-III
    Show answer

    Answer: B · A-II, B-IV, C-III, D-I

    Hooke's law holds on the straight part up to P, the proportional limit. Q, just beyond, is the yield point. The peak R is the ultimate tensile strength, and the wire breaks at S.

    • A: Interchanges the proportional limit and the yield point.
    • C: Interchanges the yield point and the peak stress.
    • D: Places fracture at the peak, though the wire breaks later.

    Remember this

    Going up the curve: proportional limit, yield point, ultimate strength, then fracture.

  6. Question 6 · Hard

    A light rigid rod hangs from wires A and B of equal length and equal cross-section, and load W is hung at distance x from wire A (drawing not to scale). For what value of x does the rod stay horizontal?

    Figure: MedExams
    Horizontal rod hung by two vertical wires with Young's moduli marked, a load at a distance x from wire A, and the rod length marked.
    1. A45 cm
    2. B18 cm
    3. C30 cm
    4. D60 cm

    Answer and explanation in LearnFree account

  7. Question 7 · Easy

    Steel is said to be more elastic than rubber. This means that, for the same stress,

    1. ASteel shows a smaller strain, so its Young's modulus is larger
    2. BSteel shows a smaller strain, so its Young's modulus is smaller
    3. CSteel shows a larger strain, so its Young's modulus is larger
    4. DSteel stretches more before it breaks

    Answer and explanation in LearnFree account

  8. Question 8 · Hard

    A steel wire (Y = 2 × 10¹¹ Pa) and a brass wire (Y = 1 × 10¹¹ Pa), of equal length L and equal cross-sectional area, are joined end to end and hung vertically with a load at the bottom. Treated as a single wire of length 2L, what is the effective Young's modulus of the combination? (Neglect the weights of the wires.)

    1. A1.5 × 10¹¹ Pa
    2. B3 × 10¹¹ Pa
    3. C1.33 × 10¹¹ Pa
    4. D0.67 × 10¹¹ Pa

    Answer and explanation in LearnFree account

  9. Question 9 · Medium

    A wire of Young's modulus 2 × 10¹¹ Pa is under a tensile stress of 2 × 10⁸ Pa, within its elastic limit. Find the elastic potential energy stored per unit volume of the wire.

    1. A2 × 10⁵ J/m³
    2. B1 × 10⁵ J/m³
    3. C1 × 10⁸ J/m³
    4. D4 × 10⁵ J/m³

    Answer and explanation in LearnFree account

  10. Question 10 · Medium

    A steel wire 2 m long, of cross-sectional area 1 mm², hangs vertically and a 100 N load is attached to its lower end. Taking Young's modulus of steel as 2 × 10¹¹ N/m², how much elastic potential energy is stored in the wire?

    1. A0.025 J
    2. B50 J
    3. C0.1 J
    4. D0.05 J

    Answer and explanation in LearnFree account

  11. Question 11 · Easy

    Poisson's ratio of a material is the ratio of

    1. Alateral strain to longitudinal strain
    2. Blongitudinal strain to lateral strain
    3. Clongitudinal stress to longitudinal strain
    4. Dshearing stress to shearing strain

    Answer and explanation in LearnFree account

  12. Question 12 · Medium

    Two wires, P and Q, are made of the same steel. P is twice as long as Q and has half its diameter. How do their Young's moduli compare?

    1. AP has twice the Young's modulus of Q
    2. BP has one-eighth the Young's modulus of Q
    3. CP has eight times the Young's modulus of Q
    4. DThey are equal, since Young's modulus depends only on the material

    Answer and explanation in LearnFree account

  13. Question 13 · Hard

    Wires A and B are made of the same material. B is twice as long as A and has twice its diameter. The same stretching force is applied to each. What is the ratio of the elastic energy stored in B to that stored in A?

    1. A1 : 1
    2. B1 : 2
    3. C2 : 1
    4. D1 : 4

    Answer and explanation in LearnFree account

  14. Question 14 · Hard

    A steel wire of diameter d and a copper wire of diameter 2d are joined end to end and loaded. Young's modulus of steel is 2 × 10¹¹ N/m² and that of copper is 1 × 10¹¹ N/m². Ignoring the weight of the wires, what is the ratio of the strain in the steel wire to that in the copper wire?

    1. A4
    2. B1/2
    3. C2
    4. D1

    Answer and explanation in LearnFree account

  15. Question 15 · Medium

    Two wires A and B are made of the same material. B has twice the length and twice the diameter of A. The same load is hung from each. What is the ratio of the extension of B to that of A?

    1. A1/4
    2. B1
    3. C1/2
    4. D2

    Answer and explanation in LearnFree account

  16. Question 16 · Medium

    Match List-I with List-II. List-I (Situation) A. A wire stretched by a hanging load B. A solid ball lying deep under water C. The top face of a block pushed sideways while its base is fixed D. A pillar holding up a roof List-II (Kind of stress) I. Shearing stress II. Compressive stress III. Tensile stress IV. Hydraulic stress Choose the correct answer from the options given below.

    1. AA-IV, B-III, C-I, D-II
    2. BA-III, B-IV, C-I, D-II
    3. CA-II, B-IV, C-I, D-III
    4. DA-III, B-I, C-IV, D-II

    Answer and explanation in LearnFree account

  17. Question 17 · Medium

    A metal cube of side 10 cm has its lower face fixed. A tangential force of 1000 N on its upper face moves that face sideways by 0.01 mm. What is the shear modulus of the metal?

    1. A1 × 10⁵ Pa
    2. B1 × 10⁸ Pa
    3. C1 × 10⁹ Pa
    4. D1 × 10¹⁰ Pa

    Answer and explanation in LearnFree account

  18. Question 18 · Easy

    On the stress-strain curve of a metal wire, what is the stress called beyond which the wire no longer regains its original length when the load is removed?

    1. AElastic limit (yield point)
    2. BFracture point
    3. CProportional limit
    4. DUltimate tensile strength

    Answer and explanation in LearnFree account

More Physics questions

Answer them one by one, keep your score and see your weak topics in Learn. Signed-out visitors try 25 per exam; sign in with Google to see them all.

Study Physics